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软件设计师每日一练试题内容(2026/1/6)
试题1
下图是一个软件项目的活动图,其中顶点表示项目里程碑,连接顶点的边表示活动,则里程碑(17)在关键路径上,关键路径长度为(18)
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试题参考答案:B、D
试题2
设用 2K×4 位的存储器芯片组成 16K×8 位的存储器(地址单元为 0000H~3FFFH,每个芯片的地址空间连续),则地址单元 0B1FH 所在芯片的最小地址编号为 ( ) 。
A、0000H
B、0800 H
C、2000 H
D、2800
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试题参考答案:B
试题3
若某个计算机系统中,内存地址与I/O地址统一编址,访问内存单元和I/O设备是靠( )采区分的。
A、数据总线上输出的数据
B、不同的地址代码
C、内存与I/O设备使用不同的地址总线
D、不同的指令
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试题参考答案:B
试题4
在进行面向对象设计时,采用设计模式能够( )。
A、复用相似问题的相同解决方案
B、改善代码的平台可移植性
C、改善代码的可理解性
D、增强软件的易安装性
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试题参考答案:A
试题5
算术表达式“(a-b)*(c+d)”的后缀式是( )。
A.ab-cd+*
B.abcd-*+
C.ab-*cd+
D.ab-c+d*
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试题参考答案:A
试题6
Ravi, like many project (1) , had studied the waterfall model of software development as the primary software life-cycle (2). He was all set to use it for an upcoming project, his first assignment. However, Ravi found that the waterfall model could not be used because the customer wanted the software delivered in stages, something that implied that the system had to be delivered and built in (3) and not as (4).
The situation in many other projects is not very different. The real world rarely presents a problem in which a standard process, or the process used in a previous project, is the best choice. To be the most suitable, an existing process must be (5) to the new problem.
A development process, even after tailoring, generally cannot handle change requests. To accommodate change requests without losing control of the project, you must supplement the development process with a requirement change management process.
(1) A. customers
B. managers
C. users
D. administrators
(2)A. activity
B. procedure
C. process
D. progress
(3) A. parts
B. modules
C. software
D. a whole
(4) A. parts
B. modules
C. software
D. a whole
(5) A. modified
B. used
C. suited
D. tailored
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试题参考答案:B、C、A、D、D
试题7
RUP 在每个阶段都有主要目标,并在结束时产生一些制品。在 ( ) 结束时产生“在适当的平台上集成的软件产品” 。
A、初期阶段
B、精化阶段
C、构建阶段
D、移交阶段
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试题参考答案:C
试题8
设有关系模式R(A1,A2,A3,A4,A5,A6),其中:函数依赖集F={A1→A2,A1A3→A4,A5A6→A1,A2A5→A6,A3A5→A6},则(1 )是关系模式R的一个主键,R规范化成都最高达到(2 )。
(1)A.A1A4
B.A2A4
C.A3A5
D.A4A5
(2)A. 1NF
B. 2NF
C. 3NF
D. BCNF
查看答案
试题参考答案:C、B
试题9
Why is(1)fun? What delights may its practitioner espect his reward? First is the
sheer joy of making things.As the child delights in his mud pie,so the adult enjoys
building things,especially things of his own design.Secong is the pleasure of making
things that are useful to other people.Third is the fascinanon of fashioning complex
puzzle-like objects of interlocking moving parts and watching them work in subtle
eyeles,playing out the consequences of principies built in from the beginning.Fourth
is the joy of always learning,which springs from the(2)nature of the task.In one way
or another the problem is ever new,and its solver learns
something:sometimes(3),sometimes theoretical,and sometimes both.Finally,there is
the delight of working in such a tractable medium.The(4),like the poet,works only
slightly removed from nure thought-stuff.Few media of ereation are so flexible,so easy
to polish and rework,so readily capable of realizing grand conceptual structures.
Yet the program(5),unlike the poet’s words,is real in the sense that it moves and
works,producing visible outputs separate from the comstrct itself.It prints
results,draws pictures,produces sounds,moves arms.Progamming then is fun because it
gratifies creative longings built deep within us and delights sensibities we hav e in
common with all men.
(1)A、programming
B、composing
C、working
D、writing
(2)A、repeating
B、basic
C、non-repeating
D、advance
(3)A、semantic
B、practical
C、lexical
D、syntactical
(4)A、poet
B、architect
C、doctor
D、programmer
(5)A、construct
B、code
C、size
D、scale
查看答案
试题参考答案:A、C、B、D、A
试题10
在关系数据库中,第三范式的主要目的是消除( )类型的问题。查看答案
试题参考答案:B
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