试题1

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试题2

（ ）  不能保证求得 0-1 背包问题的最优解。
A、分支限界法
B、贪心算法
C、回溯法
D、动态规划策略

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试题3

一个类是  （1）。在定义类时，将属性声明为private的目的是  （2）。
（1） A．一组对象的封装
B．表示一组对象的层次关系
C．一组对象的实例
D．一组对象的抽象定义
（2）A．实现数据隐藏，以免意外更改
B．操作符重载
C．实现属性值不可更改
D．实现属性值对类的所有对象共享

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试题4

两个同符号的数相加或异符号的数相减，所得结果的符号位SF和进位标志CF进（ ）运算为1时，表示运算的结果产生溢出。
A、与
B、或
C、与非
D、异或

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试题5

In a world where it seems we already have too much to do, and too many things to think about, it seems the last thing we need is something new that we have to learn.
But use cases do solve a problem with requirements: with （1 ） declarative requirements it's hard to describle steps and sequences of events.
Use cases, stated simply, allow description of sequences of events that, taken together, lead to a system doing something useful. As simple as this sounds, this is important. When confronted only with a pile of requiements, it's often（2 ）to make sense of what the authors of the  requirements really wanted the system to do. In the preceding example, use cases reduce the ambiguity of the requirements by specifying exactly when and under what conditions certain behavior occurs; as such, the sequence of the behaviors can be regarded as a requirement. Use cases are particularly well suited to capture approaches. Although this may sound simple, the fact is that (3 ) requirement capture approaches, with their emphasis on declarative requirements and "shall" statements, completely fail to capture fail to capture the (4 ) of the system's behavior. Use cases are a simple yet powerful way to express the behavior of the system in way that all stakeholders can easily understand.
But, like anything, use cases come with their own problems, and as useful as they are, they can be (5 ). The result is something that is as bad, if not worse, that the original problem. Therein it's important to utilize use cases effectively without creating a greater problem than the one you started with.
（1）A.plenty
B.loose
C.extra
D.strict
（2）A.impossible
B.possible
C.sensible
D.practical
（3）A.modern
B.conventional
C.different
D.formal
（4）A.statics
B.nature
C.dynamics
D.originals
（5）A.misapplied
B.applied
C.used
D.powerful

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试题6

在面向对象软件开发过程中，采用设计模式（ ）。
A、允许在非面向对象程序设计语言中使用面向对象的概念  
B、以复用成功的设计和体系结构 
C、以减少设计过程创建的类的个数  
D、以保证程序的运行速度达到最优值

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试题7

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试题8

设某语言的语法规则用上下文无关文法 G=(N,T,P,S)表示，其中 N 是非终结符号的集合，T是终结符号的集合，P 是产生式集合，S 是开始符号，令 V=N∪T，那么符合该语言的句子是（ ） 。
A、从 S 出发推导的、仅包含 T 中符号的符号串
B、从 N 中符号出发推导的、仅包含 T 中符号的符号串
C、从 S 出发推导的、包含 V 中符号的符号串
D、从 N 中符号出发推导的、包含 V 中符号的符号串

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试题9

冗余技术通常分为 4 类，其中  （ ）  按照工作方法可以分为静态、动态和混合冗余。
A、时间冗余
B、信息冗余
C、结构冗余
D、冗余附加技术

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试题10

模块A直接访问模块B的内部数据，则模块A和模块B的耦合类型为（）。
A．数据耦合
B．标记耦合
C．公共耦合
D．内容耦合

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