试题1

下图属于 UML 中的（1），其中,AccountManagement 需要（2）。

（1）A、组件图
B、部署图
C、类图
D、对象图
（2）A、实现 IdentityVerifier 接口并被 CreditCardServices 调用
B、调用 CreditCardServices 实现的 IdentityVerifier 接口
C、实现 IdentityVerifier 接口并被 Logger 调用
D、调用 Logger 实现的 IdentityVerifier 接口

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试题2

美国卡内基—梅隆大学SEI提出的CMM模型将软件过程的成熟度分为5个等级，以下选项中，属于可管理级的特征是（ ）。
A、工作无序，项目进行过程中经常放弃当初的计划 
B、建立了项目级的管理制度 
C、建立了企业级的管理制度 
D、软件过程中活动的生产率和质量是可度量的 

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试题3

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试题4

Software entities are more complex for their size than perhaps any other humanconstruct, because no two parts are alike （at least above the statement level）. If they are, wemake the two similar parts into one, a（ 71 ）, open or closeD． In this respect software systemsdiffer profoundly from computers, buildings, or automobiles, where repeated elements abound．
Digital computers . are themselves more complex than most things people build;they have very large numbers of states This makes conceiving, describing, and testing them harD． Software systems have orders of magnitude more（ 72 ）than computers do
Likewise, a scaling-up of a software entity is not m erely a repetition of the same elementsm larger size; it is necessarily an mcrease in the number of different elements. In most cases, the elements interact with each other in some（ 73 ）fashion: and the complexity of the wholencreases much more than linearly.
The complexity of software is a（an）（ 74 ）property, not an accidental one Hencedescriptions of a software entity that abstract away its complexity often abstract away its essence.Mathematics and the physical sciences made great strides for threecenturies by constructingsimplified models of complex phenomena, deriving properties fiom the models, and verifyingthose properties experimentally. This worked becausethe complexities（ 75 ） in the modelswere not the .essential properties of the phenomena: It does not work when the complexities are the essence.
Many of the classical problems of developing software products derive from this essential complexi and its nonlinear uicreases with size. Not only .technical problems but management problems as well come from the coin plexity.
A． task
B．job
C．subroitune
D．Program
A．states
B．parts
C．conditions
D．Expressions
A．linear
B. nonlinear
C．Parallel
D．Addititive
A. surface
B． Outside
C．exterior
D．Essential
A． fixed
B． Included
C．ignored
D．stabilized

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试题5

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试题6

使用 PERT 图进行进度安排，不能清晰地描述  （1）  ，但可以给出哪些任务完成后才能开始另一些任务。下面 PERT 图所示工程从 A 到 K 的关键路径是  （2）  ，（图中省略了任务的开始和结束时刻）。

（1）A、每个任务从何时开始
B、每个任务到何时结束
C、各任务之间的并行情况
D、各任务之间的依赖关系
（2）A、ABEGHIK
B、ABEGHJK
C、ACEGHIK
D、ACEGHJK

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试题7

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试题8

对于一个大型软件来说，不加控制的变更很快就会引起混乱。为有效地实现变更控制，需借助于配置数据库和基线的概念。  （ ）  不属于配置数据库。
A、开发库
B、受控库
C、信息库
D、产品库

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试题9

运行下面的 C 程序代码段，会出现（  ）错误。
int k=0；
for（；k<100;）；
{k++；）
A．变量未定义
B．静态语义
C．语法
D．动态语义

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试题10

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